12n^2+28n+20=4

Solution for 12n^2+28n+20=4 equation:

Simplifying
12n2 + 28n + 20 = 4

Reorder the terms:
20 + 28n + 12n2 = 4

Solving
20 + 28n + 12n2 = 4

Solving for variable 'n'.

Reorder the terms:
20 + -4 + 28n + 12n2 = 4 + -4

Combine like terms: 20 + -4 = 16
16 + 28n + 12n2 = 4 + -4

Combine like terms: 4 + -4 = 0
16 + 28n + 12n2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(4 + 7n + 3n2) = 0

Factor a trinomial.
4((4 + 3n)(1 + n)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(4 + 3n)' equal to zero and attempt to solve:

Simplifying
4 + 3n = 0

Solving
4 + 3n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3n = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 3n = 0 + -4
3n = 0 + -4

Combine like terms: 0 + -4 = -4
3n = -4

Divide each side by '3'.
n = -1.333333333

Simplifying
n = -1.333333333
Subproblem 2
Set the factor '(1 + n)' equal to zero and attempt to solve:

Simplifying
1 + n = 0

Solving
1 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + n = 0 + -1
n = 0 + -1

Combine like terms: 0 + -1 = -1
n = -1

Simplifying
n = -1
Solution
n = {-1.333333333, -1}